Question

The highest power of 3 that completely divides 40!

• A. 18
• B. 15
• C. 16
• D. 17

Answer 1

The correct option is A 18

No of 3's in $40!=\left[\frac{40}{3}\right]+\left[\frac{40}{9}\right]+\left[\frac{40}{27}\right]=$13 + 4 + 1 = 18.
Option (a) is correct.