Question

The highest score in an inning was $\frac{3}{11}$ of the total and the next highest was $\frac{3}{11}$ of the remainder. If the Scores differed by 9 the total score was

• A. $110$
• B. $121$
• C. $132$
• D. $143$

Answer 1

The correct option is B $121$

Let the total score $=x$
Highest score $=\frac{3}{11}x,$ Remainder $=x-\frac{3x}{11}=\frac{8x}{11}$
$\therefore Nexthighestscore=\frac{3}{11}of\frac{8x}{11}=\frac{24x}{121}$
Given difference of the two scores = 9
$\Rightarrow \frac{3x}{11}-\frac{24x}{121}=9\Rightarrow \frac{33x-24x}{121}=9$
$\Rightarrow \frac{9x}{121}=9\Rightarrow x=\frac{9\times 121}{9}\Rightarrow x=121$