Question

The highest temperature in $(°C)$ in a last week of May in Delhi was recorded as follows :

Days	Mon	Tue	Wed	Thu	Fri	Sat	Sun
Temperature (in $°C$)	$38$	$40$	$44$	$45$	$43$	$40$	$35$

Find the range, mean and median of the above data.

Answer 1

Step $\mathbf{1}$: Find the range of the above data:

Highest temperature observed is $45°\text{C}$.

and, lowest temperature observed is $35°\text{C}$.

Therefore, range $=$ highest observation $-$ lowest observation

$=(45-35)°\text{C}$

$=10°\text{C}$

Hence, the range of the above data is $\mathbf{10}\mathbf{°}\mathbf{}\mathbf{\text{C}}$.

Step $\mathbf{2}$: Find the mean of the above data:

Total number of days $=7$

Sum of the temperatures observed $=38+40+44+45+43+40+35$

$=285$

Mean $=\frac{\text{sum of the temperatures observed}}{\text{total number of days}}$

$=\frac{285}{7}=40.71$

So, the mean of the above data is $\mathbf{40}\mathbf{.}\mathbf{71}$.

Step $\mathbf{3}$: Find the median of the above data

Arrange the given data in ascending order :

$35,38,40,40,43,44,45$

Here, n $=7$, which is odd.

So, Median $=$Value of $\frac{1}{2}{(\text{n}+1)}^{\text{th}}$ observation

Median of above data $=$ Value of $\frac{1}{2}{(7+1)}^{\text{th}}$ term

$=$ Value of $4^{\text{th}}$ term

$=40$

So, the median of the above data is $\mathbf{40}$.