The highly water soluble alkaline earth metal fluoride is:

C a F_{2}

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B a F_{2}

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M g F_{2}

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B e F_{2}

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Solution

The correct option is C $B e F_{2}$
Beryllium fluoride is highly water soluble. The small sized $B e^{2 +}$ ion has high hydration energy which more than compensates for the lattice energy. Other alkaline earth metals form fluorides which are insoluble in water.

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B e F_{2}

L i F, B e F_{2}, N a_{3} P O_{4}, K_{3} P O_{4}, B a F_{2}, M g F_{2}, L i_{3} P O_{4}, N a F, C s F, C a F_{2}, M g_{3} (P O_{4})_{2}

B e F_{2}, M g F_{2}, C a F_{2}

B a F_{2}

B e^{2 +}, M g^{2 +}, C a^{2 +}, B a^{2 +}

F^{-} - 2494, - 1921, - 1577, - 1305

BeF₂ is more soluble in water, where as the fluoride of other alkaline earth metals are insoluble because of

B e F_{2}

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