The $H N H$ angle value is higher than $H P H, H A s H$ and $H S b H$ angles. Why?

Open in App

Solution

The central atom in group 15 hydrides is $s p^{3}$ hybridized. One lone pair is present in one of the $s p^{3}$ hybrid orbital and the molecule has pyramidal geometry. On moving down the group 15, atomic size increases and electronegativity decreases. The bond pairs of electrons become more and more away from the central atom. This decreases the repulsion in the bond pairs and decreases the bond angle.

Suggest Corrections

Similar questions

The HNH angle value is higher than HPH, HAsH and HSbH angles. Why? [Hint: Can be explained on the basis of sp³ hybridisation in NH₃ and only s−p bonding between hydrogen and other elements of the group].

The H-N-H angle vlaue is higher than H-P-H, H-AsH and H-SbH angles. Why?

Q. Bond angle in

H_{2} O

(104.5

^{\circ}

) is higher than the bond angle of

H_{2} S

(92.1

^{\circ}

). The difference is due to:

Join BYJU'S Learning Program

The HNH angle value is higher than HPH,HAsH and HSbH angles. Why?

The $H N H$ angle value is higher than $H P H, H A s H$ and $H S b H$ angles. Why?