The hole $40_{+ 0.000}^{+ 0.000}$ and shaft, $4_{- 0.010}^{+ 0.010}$ when assembled will result in

Drive fit

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Interference fit

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Clearance fit

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Transition fit

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Solution

The correct option is D Transition fit
The hole $40_{+ 0.000}^{+ 0.000}$ and shaft, $4_{- 0.010}^{+ 0.010}$ when assembled will result in Transition fit.

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Similar questions

ϕ 9^{\begin{matrix} + 0.015 + 0.000 \end{matrix}} m m

ϕ 9^{\begin{matrix} + 0.010 + 0.001 \end{matrix}} m m

Consider a hole - shaft interchangeable assembly as 40 H \begin{matrix} + 0.02 0.000 \end{matrix} j \begin{matrix} + 0.01 - 0.01 \end{matrix} .

The allowance (in microns) in the assembly is

Shafts of size {25.000}_{- 0.0100}^{- 0.040} m m mate with

Holes of size {25.000}_{- 0.000}^{+ 0.020} m m .

A hole dimension 30 \begin{matrix} + 0.025 + 0.000 \end{matrix} is assembled

with a shaft of 30 \begin{matrix} - 0.009 - 0.025 \end{matrix} mm.

The type of fit during the assembly is

A shaft of {20.00}_{- 0.005}^{+ 0.015} m m diameter

A hole of {20.00}_{+ 0.025}^{- 0.010} m m diameter

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