The hollow sphere, in which the circus motor cyclist performs his stunts, has a diameter of 7 m. Find the area available to the motor cyclilst for riding.

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Solution

Diameter of hollow sphere = 7 m
$∴ R a d i u s (r) = \frac{7}{2} m$
Now its surface area
$= 4 π r^{2} = 4 \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} m^{2} = 154 m^{2}$

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In a circus, a motorcyclist performs his stunts inside a hollow sphere. The thickness of the sphere is negligible. If the diameter of the hollow sphere is 14 m, then find the area available for the motorcyclist to perform his stunts.
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The hollow sphere, in which the circus motor cyclist performs his stunts, has a diameter of 7 m. Find the area available to the motor cyclilst for riding.

Diameter of hollow sphere = 7 m ∴ Radius (r)=72m Now its surface area =4πr2=4×227×72×72m2=154m2

Diameter of hollow sphere = 7 m
$∴ R a d i u s (r) = \frac{7}{2} m$
Now its surface area
$= 4 π r^{2} = 4 \times \frac{22}{7} \times \frac{7}{2} \times \frac{7}{2} m^{2} = 154 m^{2}$