The horizontal and vertical components of the velocity of projection of a projectile are 10ms−1 and 20ms−1 respectively. Find the horizontal range of projectile. (g=10ms−2).
A
20m
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B
40m
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C
50m
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D
45m
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Solution
The correct option is B40m Range of a projectile =u2sin2θg ⇒R=2(usinθ)(ucosθ)g R=2uyuxg =2×20×1010 =40m