Question

The horizontal component $N_x$ and vertical component $N_y$ of the reaction at end P are given by:

• A. $N_x$ $=$ $1300N,N_y=960N$
• B. $N_x=960N,N_y=140N$
• C. $N_x=960N,N_y=960N$
• D. $N_x=1300N,N_y=1300N$

Answer 1

The correct option is B $N_x=960N,N_y=140N$

For equilibrium,$\sum F_x=0$ thus
$Tcos{37}^0-N_x=0$
$N_x=\frac{4}{5}T$
$=\frac{4}{5}\left(1200\right)$
$=960N$
$\sum F_y=0$, thus
$N_y-Tsin{37}^0+500+80=0$
or
$N_y=\left(1200\right)\left(\frac{3}{5}\right)-500-80$
$=140N$