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Byju's Answer
Standard XIII
Physics
Vector Component
The horizonta...
Question
The horizontal component of a force of
10
N
inclined at
30
o
to vertical is
A
3
N
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B
5
√
3
N
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C
5
N
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D
10
√
3
N
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Solution
The correct option is
C
5
N
Given,
F
=
10
N
,
θ
=
30
o
Horizontal component (
F
H
)=
F
sin
θ
F
H
=
10
sin
30
=
10
×
1
2
=
5
N
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