The horizontal component of a projectile velocity is 2 m/s. The equation of the projectile is $y = 16 x - (\frac{5}{4}) x^{2} .$ If $g = 10 m / s^{2},$ the horizontal range is

16 m

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8 m

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3.2 m

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12.8 m

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Solution

The correct option is D 12.8 m
$\begin{matrix} G i v e n, y = 16 x - (\frac{5}{4}) x^{2} y = 16 x ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ 1 - \frac{x}{(\frac{64}{5})} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦ ∴ R = \frac{64}{5} = 12.8 ∴ O p t i o n D i s c o r r e c t . \end{matrix}$

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