CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equipotential Surfaces

The horizonta...

Question

The horizontal component of earth magnetic field at a place is square root of 3 times the vertical component .what is the angle of dip at that place

Open in App

Solution

tangent of Angle of dip = vertical component of earth's field ÷ horizontal component of the field

tan δ = vertical component ÷ (1÷√3)vertical component

tanδ = 1÷√3
δ = 30owhere δ is angle of dip.

Like if satisfied

Suggest Corrections

thumbs-up

1

Similar questions

Q. At a certain place the horizontal component of earth's magnetic field is

\sqrt{3}

times the vertical component. The angle of dip at that place is

Q. At a place of Earth, the vertical component of Earth's magnetic field is

\sqrt{3}

times its horizontal component. The angle of dip at this place is _____.

Q. The horizontal component of earth's magnetic field at a place is

\frac{1}{\sqrt{3}}

times the vertical component. Determine the angle of dip at that place.

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Equipotential Surfaces

PHYSICS

Watch in App

explore_more_icon

Explore more

Equipotential Surfaces

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon