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Equipotential Surfaces

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Question

The horizontal component of earth magnetic field at a place is square root of 3 times the vertical component .what is the angle of dip at that place

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Solution

tangent of Angle of dip = vertical component of earth's field ÷ horizontal component of the field

tan δ = vertical component ÷ (1÷√3)vertical component

tanδ = 1÷√3
δ = 30owhere δ is angle of dip.

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