Question

The horizontal component of the earth's magnetic field is 0.22 gauss and total magnetic field is 0.4 gauss. The angle of dip is:

• A. $ta{n}^{-1}\left(\infty \right)$
• B. $ta{n}^{-1}\left(1\right)$
• C. $ta{n}^{-1}\left(1.518\right)$
• D. $ta{n}^{-1}\left(\pi \right)$

Answer 1

Answer: (C)

$ta{n}^{-1}\left(1.518\right)$

By using $B_H=Bcos\varphi$

$\Rightarrow$ $\varphi =\frac{B_H}{B}=\frac{0.22}{0.4}$

$\Rightarrow$ $tan\varphi =\frac{\sqrt{(0.4{)}^2-(0.22{)}^2}}{0.22}=1.518$

$\Rightarrow$ $\varphi =ta{n}^{-1}\left(1.518\right)$