Question

The horizontal component of the flux density of earth's magnetic field is $1.7\times {10}^{-5}T$. The value of the horizontal component of the intensity of earth's magnetic field will be:

• A. $24.5A{m}^{-1}$
• B. $13.5A{m}^{-1}$
• C. $1.53A{m}^{-1}$
• D. $0.35A{m}^{-1}$

Answer 1

The correct option is B $13.5A{m}^{-1}$

Since, $H=B/{\mu }_o$
$H=7\times {10}^{-5}/4\pi \times {10}^{-7}$
$H=13.5A{m}^{-1}$
Hence option(B)