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Question

The horizontal distance covered by a projectile fired with an initial velocity v at an angle θ with the horizontal, is given by
H(v,θ)=v2sin(2θ)32
If a ball is kicked with an initial velocity of 30 feet per second at an angle of 50 degrees with the horizontal, find the horizontal distance, in feet, from the point where the football is kicked to the point where the football first hits the ground.

A
28
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B
30
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C
33
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D
36
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E
39
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Solution

The correct option is A 28
Given, H(v,θ)=v2sin2θ32
Here v=30 feet per second, angle θ=50
H(v,θ=(30)2sin(2×50)32
= 900sin10032
= 900×0.984832=27.7028

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