Question

The horizontal range of a projectile is R and maximum height attained by it be H. A strong wind now begins to blow in the direction of horizontal motion of projectile, giving it a constant acceleration equal to g. Under the same conditions of projection, the new range is______-_

Answer 1

Time taken by projective to reach ground S= ut + ½ at² H=0*t+1/2 gt² total time= 2 * (2H/g)^1/2 S= ut + ½ at²
= R + ½ * g *2* ((2H/g)^1/2)²
=R + g *2 H/g
=R+ 2H