The horn of a car emits sound with a dominant frequency of 2400 Hz. What will be the apparent dominant frequency heard by a person standing on the road in front of the car if the car is approaching at 18.0 km/h ? Speed of sound in air = 340 m/s.

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Solution

$f_{1} = (\frac{u + v_{m} - v_{0}}{v + v_{m} - v_{s}}) F$

[18 km/h=5 m/s]

Using sign conventions App. frequency,

$= (\frac{340 + 0 - 0}{340 + 0 - 5}) \times 2400$

=2436 Hz

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The horn of a car emits sound with a dominant frequency of 2400 Hz. What will be the apparent dominant frequency heard by a person standing on the road in front of the car if the car is approaching at 18.0 km/h ? Speed of sound in air = 340 m/s.

f1=(u+vm−v0v+vm−vs)F [18 km/h=5 m/s] Using sign conventions App. frequency, =(340+0−0340+0−5)×2400 =2436 Hz

$f_{1} = (\frac{u + v_{m} - v_{0}}{v + v_{m} - v_{s}}) F$

[18 km/h=5 m/s]

Using sign conventions App. frequency,

$= (\frac{340 + 0 - 0}{340 + 0 - 5}) \times 2400$

=2436 Hz