Question

The houses of 4 friends are located at the points (6, 6), (0, 6), (3, 3) and (6, 0) as shown in the figure. A, C and B are the vertices of a right triangle. Find the distance between the houses at points B and D.

• A. 3$\sqrt{2}\text{units}$
• B. 2$\sqrt{5}\text{units}$
• C. 2$\sqrt{3}\text{units}$
• D. $\sqrt{6}\text{units}$

Answer 1

The correct option is A 3$\sqrt{2}\text{units}$

$\text{Distance between two points}(x_1,y_1)\text{and}(x_2,y_2)\text{is}\sqrt{(x_2-x_1{)}^2+(y_2-y_1{)}^2}\therefore \text{Distance between the houses at points B and D}=\sqrt{(3-0{)}^2+(3-6{)}^2}=\sqrt{9+9}=3\sqrt{2}\text{units}$