Question

The hybridisation of carbon in diamond, graphite and acetylene is:

• A. $s{p}^3,sp,s{p}^2$
• B. $sp,s{p}^2,s{p}^3$
• C. $s{p}^3,s{p}^2,sp$
• D. $s{p}^2,s{p}^3,sp$

Answer 1

Answer: (C)

$s{p}^3,s{p}^2,sp$

Hybridization of $C$ in diamond- $s{p}^3$ since, all the 4 valence electrons of carbon participate in bonding.

Hybridization of $C$ in graphite- $s{p}^2$ because only 3 electrons of carbon participate in bonding.

Hybridization of $C$ in acetylene- $sp$ because of the presence of triple bond on carbon.

Option C is correct.