Question

The hybridisation of carbons $C_1$ and $C_3$ in the compound:
1 2 3 4
$C{H}_3-CH=CH-C{H}_3$

• A. $s{p}^3,s{p}^2$
• B. $s{p}^2,s{p}^2$
• C. $s{p}^3,s{p}^3$
• D. $s{p}^2,s{p}^3$

Answer 1

The correct option is A $s{p}^3,s{p}^2$

$\stackrel{1}{C{H}_3}-\stackrel{2}{CH}=\stackrel{3}{CH}-\stackrel{4}{C{H}_3}$

$C-1$ is a single bond. so $s{p}^3$

$C-3$ is double bond, so $s{p}^2$