Question

The hybridisation of central atom is not $s{p}^{3}d$ in:

• A. $PC{l}_5$
• B. $Br{F}_3$
• C. $Xe{F}_2$
• D. $Br{F}_5$

Answer 1

Answer: (D)

$Br{F}_5$

$s{p}^{3}d$ hybridisation means total of $5$ hybrid orbitals but in D) Bromine pentafluoride we require $6$ hybrid orbitals - $5$ Bond pairs and $1$ lone pair so its hybridisation would be $s{p}^3{d}^2$ and hence, the answer.