The Hybridisation of O atom in H2O is
Using VSEPR theory, no of valence electrons = 6
Ligands = 2
A,C = 0
(V+L+A−C)2 =4
Hence the Hybridization is sp3
The shape is bent (since 2 lone pairs are there on O atom). Hence bond angle is slightly lesser than 109.5∘ (ideal tetrahedral angle )
Bond angle = 104.5∘