Question

The hybridisation of orbitals of N atom in $N{O}_3^{-},N{O}_2^{+}andN{H}_4^{+}$ are respectively

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

The formula to find the hybridisation of central atom is Z=1/2[number of valence electrons on central atom
+ no. of monovalent atoms attached to it + charge if any – positive charge if any]
$forN{O}_3^{-},Z=1/2[5+0+1-0]=3-----s{p}^2,forN{O}_2^{+},Z=1/2[5+0+0-1]=2-----sp,forN{H}_4^{+}=1/2[5+4+0-1]=4-s{p}^3$