Question

The hybridisation of sulphur in $S{F}_6$ is:

• A. $s{p}^2$
• B. $s{p}^3$
• C. $s{p}^3{d}^2$
• D. $s{p}^{3}d$

Answer 1

Answer: (C)

$s{p}^3{d}^2$

Here, sulphur forms $6$ bond pairs. It thus, needs $6$ hybrid orbitals and therefore, hybridization is $s{p}^3{d}^2$.