The hybridisations of atomic orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-}, and N H_{4}^{+}$ respectively are

s p, s p^{3}, and s p^{2}

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s p^{2}, s p^{3}, and s p

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s p, s p^{2}, and s p^{3}

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s p^{2}, s p, and s p^{3}

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Solution

The correct option is C $s p, s p^{2}, and s p^{3}$

It has 2 $σ$ bond pair, so N has $s p$ hybridisation.

It has 3 $σ$ bond pair, so N has $s p^{2}$ hybridisation.

It has 4 $σ$ bond pair, so N has $s p^{3}$ hybridisation.
Option C is the correct answer

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Similar questions

The hybridisation of atomic orbitals of nitrogen in ${N O_{2}}^{+}$ , ${N O_{3}}^{-}$ and ${N H_{4}}^{+}$ are:

N

N O_{2}^{+}, N O_{3}^{-}

N H_{4}^{+}

s p^{3}

N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}, N F_{3}

N O_{2}^{+}

N O_{3}^{-}

N H_{4}^{+}

The hybridisation of atomic orbitals of nitrogen in ${N O_{2}}^{+}$ , ${N O_{3}}^{-}$ and ${N H_{4}}^{+}$ are:

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