The hybridisations of BCl3 and NCl3 respectively are:
A
sp2 and sp3
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B
sp3 and sp2
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C
sp and sp3
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D
sp2 and sp2
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Solution
The correct option is Asp2 and sp3 The steric number of BCl3 =12(3+3+0)=3 So, it is sp2 hybridized and has three bond pairs and zero lone pairs. Thus, the shape is trigonal planar.
Similarly, NCl3 has a steric number of =12(5+3)=4 So, it is sp3 hybridized. It has three bond pairs and one lone pair resulting in tetrahedral geometry.