Question

The hybridised state of $Cu$ in $\left[Cu\right(N{H}_3{)}_4{]}^{2+}$ is:

• A. $sp$
• B. ${sp}^2$
• C. ${sp}^3$
• D. ${dsp}^2$

Answer 1

The correct option is D ${dsp}^2$


$Cu\left[\right(N{H}_3{)}_4{]}^{2+}$

(Refer to Image)

Hence hybridised state of $Cu$ is $ds{p}^2$ .