The hybridization associated with the central atom of a molecule in which all the bond angles are $120^{o}$ is _________

s p

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{S p}^{2}

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{s p}^{3}

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{s p}^{3} d

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{s p}^{3} d^{2}

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Solution

The correct option is D ${S p}^{2}$
In $s p^{3} d$ type of hybridisation, shape of molecule is trigonal bipyramidal and bond angle will be of $120^{o}$

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Similar questions

The correct order of hybridization of the central atom in the following species $N H_{3}, [P t C l_{4}]^{2 -}$ , $P C l_{5}$ and $B C l_{3}$ is

B e H_{2}

C H_{2} B r_{2}

P F_{6}^{-}

B F_{3}

C H_{4}, C_{2} H_{6}, a n d C_{2} H_{4}

Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

(N_{3}^{-}, N O C l, N_{2} O)

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