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Question

The hybridization involved in complex [Ni(CN)4]2 is:


[Atomic number of Ni =28]

A
d2sp2
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B
d2sp3
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C
dsp2
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D
sp3
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Solution

The correct option is C dsp2
[Ni(CN)4]2 is an square planar complex with dsp2 hybridization.

The outer electronic configuration of Ni2+ ion is 3d84s0.

One 3d, one 4s and two 4p orbitals undergo dsp2 hybridization four equivalent dsp2 hybrid orbitals which are occupied by 4 electron pairs of 4 cyanide ligands.

This forms [Ni(CN)4]2.

Hence, option C is correct.

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