Question

The hybridization, lone pair of electrons and shape of $I_3^{-}$ is:

• A. it has $s{p}^{3}d$ hybridization
• B. it has trigonal bipyramidal shape
• C. it is linear
• D. it has 3 lone pair of electrons

Answer 1

Answer: (A), (C), (D)

The correct options are
A it has $s{p}^{3}d$ hybridization
C it is linear
D it has 3 lone pair of electrons

Hybridization-to find the no.of hybridized bonds, add the no. of lone pairs with the no.of neighbour atoms.

$3l.p+2\left(iodineatoms\right)=5$
So Hybridization of $l_3-$=${sp}^{3}d$

$Note:$ These are the hyb. numbers that represent the type of hybridization.

$2\sim sp$

$3\sim {sp}^2$

$4\sim s{p}^3$

$5\sim {sp}^{3}d$

$6\sim {sp}^3{d}^2$

lone pairs - 3
Shape - Linear with a bend angle of $180°$. The lone pairs are arranged in a trigonal bipyramidal arrangement.