The hybridization of 1st and 2nd Carbon atoms in propadiene is:

{s p}^{3}, {s p}^{2}

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{s p}^{2}, s p

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{s p}^{2}, {S p}^{2}

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s p, s p

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Solution

The correct option is B ${s p}^{2}, s p$
$P r o p a d i e n e$
Answer $B .$ , $s p^{2}, s p$

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