The hybridization of boron in $B_{2} H_{6}$ is

s p^{2}

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s p

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s p^{3}

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s p^{3} d

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Solution

The correct option is C $s p^{3}$

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Similar questions

B_{2} H_{6}

B_{2} H_{6}

(B_{2} H_{6})

B

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H_{3} B O_{3}

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B_{2} H_{6}

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