The hybridization of carbon atoms in $C - C$ single bond of $C H \equiv C - C H = C H_{2}$ is :

s p^{3} - s p^{3}

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s p^{2} - s p^{3}

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s p - s p^{2}

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s p^{3} - s p

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Solution

The correct option is C $s p - s p^{2}$
$\equiv C -$ has $2 σ$ and $2 π$ bonds and has $s p$ -hybridization.

$- C H =$ has $3 σ -$ and $1 π -$ and has $s p^{2}$ -hybridization.

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Similar questions

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

In the compound $C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H$ ,the $C_{2} - C_{3}$ bond is of the type

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

In the molecule CH ≡ C -CH = $C H_{2}$ , the hybridisation of C -Cbond is

C (1) H_{2} = C (2) H - C (3) \equiv C H

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