The hybridization of carbon atoms in C-C single bond of $H C$ $\equiv$ $C - C H =$ $C H_{2}$ is :

s p^{3} - s p^{3}

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s p^{2} - s p^{3}

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s p - s p^{2}

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s p^{3} - s p

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Solution

The correct option is B $s p - s p^{2}$
The left carbon atom has 2 bond pairs making it $s p$ whereas the right C atom has 3 bond pairs making it $s p^{2}$ .

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