The hybridization of central metal ion and shape of Wilkinsons catalyst is:

d s p^{2}

, square planar

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

s p^{3}

, tetrahedral

No worries! We‘ve got your back. Try BYJU‘S free classes today!

s p^{3} d

, trigonal bipyramidal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

d^{2} s p^{3}

, octahedral

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $d s p^{2}$ , square planar
In this complex central atom Rh has $d^{8}$ configuration and form low spin square planar complex ( $d s p^{2}$ ).

Suggest Corrections

Similar questions

Shape of the molecule having ${d s p}^{2}$ and $d^{2}$ ${s p}^{3}$ hybridisation is respectively:

X e F_{4}

The geometry and the type of hybrid orbitals present about the central atom in $B F_{3}$ is

P C l_{4}^{+}, P C l_{4}^{-}

A s C l_{5}

[X e F_{5}]^{-}

X e O_{3} F_{2},

Join BYJU'S Learning Program