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Question

The hybridization of iodine in IF5 is:

A
sp3d
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B
sp3d2
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C
sp3d3
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D
sp3
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Solution

The correct option is B sp3d2
Electronic configuration of iodine=[Kr]4d105s25p5
Thus it has 7 valence electrons.
5 valence electrons are used to hold 5 fluorine atoms while 2 valence electrons form one lone pair of electrons.
Thus, its steric number is 5+1=6. This implies sp3d2 hybridisation.
Hence option (b) is the correct answer.

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