Question

The hybridization of iron in $K_4\left[Fe\right(CN{)}_6]$ is?

• A. $ds{p}^2$
• B. $s{p}^3$
• C. $d^{2}s{p}^3$
• D. $d^{2}s{p}^2$

Answer 1

Answer: (C)

$d^{2}s{p}^3$

Iron(Fe) is atomic no 26.In which 6 electrons are in 3d orbitals and 2 electrons are there in 4s orbital.

In this complex, it exists in +2 oxidation state.

When ligands CN approach to the central metal atom, the electrons remains in the inner orbital.And 6 electron pairs of 6CN's are filled in 2d,1s and 3p orbitals.

Hence theHybridisation is $d^{2}s{p}^3$