Question

The hybridization of N atom in $N{O}_3^{-},N{O}_2^{-}$ and $N{H}_4^{-}$ respectively is:

• A. $s{p}^2,s{p}^3,sp$
• B. $sp,s{p}^3,s{p}^2$
• C. $sp,s{p}^2,s{p}^3$
• D. $s{p}^2,sp,s{p}^3$

Answer 1

Answer: (D)

$s{p}^2,sp,s{p}^3$

The Hybridization of N atom in $N{O}_3^{-}$, $N{O}_2^{-}$ and $N{H}_4^{-}$ is $s{p}^2,sp,s{p}^3$ respectively.
In $N{O}_3^{-}$, the central N atom has 3 bonding domains (one single bond and two double bonds) and zero lone pairs of electrons.
In $N{O}_2^{-}$ the central N atom has 2 bonding domains (one single bond and one double bond) and zero lone pairs of electrons.
In $N{H}_4^{-}$the central N atom has 4 bonding domains (4 single bonda) and zero lone pairs of electrons.