The hybridization of nitrogen in pyrrole is:

s p^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

s p^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

s p

No worries! We‘ve got your back. Try BYJU‘S free classes today!

cannot be predicted

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $s p^{2}$
In pyrrole lone pair of nitrogen are in conjugation with double bond electrons to make it aromatic compound so here nitrogen is $s p^{2}$ hybridized.

Suggest Corrections

Similar questions

C H_{4}, C_{2} H_{6}, a n d C_{2} H_{4}

Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

s p, s p^{2} a n d s p^{3}

(N_{3}^{-}, N O C l, N_{2} O)

N O_{2}^{+}, N O_{3}^{-}

N H_{4}^{+}

Join BYJU'S Learning Program