The hybridization of P in phosphate ion $(P O_{4}^{3 -})$ is the same as in :

I

I {C l}_{4}^{-}

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S

S O_{3}

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N

N O_{3}^{-}

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S

S O_{3}^{2 -}

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Solution

The correct option is D $S$ in $S O_{3}^{2 -}$
In $(P O_{4}^{3 -})$ , $P$ has a hybridisation of $s p^{2}$ which is the same as that of $S$ in $S O_{3}^{2 -}$ because of 3 bond pairs present.

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Similar questions

The hybridization of $P$ is $P O_{4}^{3 -}$ is the same as of:

P

P O_{4}^{3 -}

N I_{3}

I_{3}^{-}

S O_{3}^{- 2}

N O_{3}^{-}

The hybridization of $P$ is $P O_{4}^{3 -}$ is the same as of:

F e (O H)_{3}

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