Question

The hybridization of $P$ in $P{O}_4^{3-}$ is the same as that of:

• A. $N$ in $N{O}_3^{-}$
• B. $S$ in $S{O}_3$
• C. $I$ in $IC{l}_2^{+}$
• D. $I$ in $IC{l}_4^{-}$

Answer 1

The correct option is C $I$ in $IC{l}_2^{+}$


$P{O}_4^{3-}$ has 4 bond pairs and hence the hybridization is $s{p}^3$ hybridized.
$N{O}_3^{-}$ has three bond pairs and hence it is $s{p}^2$ hybridized.
$S{O}_3$ has three bond pairs and hence its is $s{p}^2$ hybridized.
$IC{l}_2^{+}$ has four bond pairs and hence it is $s{p}^3$ hybridized.
$IC{l}_4^{-}$ has four bond pairs and two lone pairs and hence it is $s{p}^3{d}^2$ hybridized.