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Question

The hybridization of P is PO3−4 is the same as of:


A

S in SO3

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B

N in NO3

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C

I in ICl+2

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D

I in ICl4

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Solution

The correct option is C

I in ICl+2


Number of hybrid orbitals of P in PO34=12[5+0+3]=4(sp3)
No. of hybrid orbitals of N in NO3=12[5+0+1]=3(sp2)
No. of hybrid orbitals of I+ in ICl+2(5s25p2x5py5Pz:(sp3)2(sp3)2(sp3)1(sp3)1
- atom in excited state: 5s25p45d1z25d0z2y2
I - atom is sp3d2 hybridised state in ICI4
(sp3d2)2(sp3d2)2(sp3d2)1(sp3d2)1(sp3d2)1(sp3d2)1
-Two lone pairs occupy the axial positions of octahedron and the shape of ICl4 becomes square planar.


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