The hybridization of sulphur in peroxodisulphuric acid is:

s p^{2}

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s p^{3}

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s p

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s p^{3} d

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Solution

The correct option is D $s p^{3}$
In peroxo disulphuric acid, the sulfur atom undergoes $s p^{3}$ hybridization since, it forms $4$ bond pairs.

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

B e H_{2}

C H_{2} B r_{2}

P F_{6}^{-}

B F_{3}

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