The hybridization of the star marked carbon in the compound is:

s p

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s p^{2}

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s p^{3}

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d s p^{2}

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Solution

The correct option is C $s p$
The hybridisation of the given compound- (star marked $C$ )
in this structure, the star marked $C$ has completed its valency $4$ and has triple bond adjacent to it. The cabon having triple bond as $s p$ hybridisation

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Similar questions

The correct order of hybridization of the central atom in the following species $N H_{3}, [P t C l_{4}]^{2 -}$ , $P C l_{5}$ and $B C l_{3}$ is

s p, s p^{2} a n d s p^{3}

C H_{4}, C_{2} H_{6}, a n d C_{2} H_{4}

C 6 H_{3} - C 5 H = C 4 H - C 3 H_{2} - C 2 \equiv C 1 H

s p, s p^{2}

s p^{3}

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