Question

The hybridization of $Xe$ in $Xe{F}_2$ is:

• A. $s{p}^3$
• B. $s{p}^2$
• C. $s{p}^{3}d$
• D. $s{p}^3{d}^2$

Answer 1

The correct option is C $s{p}^{3}d$

$Xe{F}_2=2+\frac{8-2}{2}$
$=2+3$

So it has 2 bond pair and 3 lone pair. Thus, it shows $s{p}^{3}d$ hybridization