The hybridization state of $C$ -atom in butenedioic acid is :

{s p}^{2}

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{s p}^{3}

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Both a and b

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s p

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Solution

The correct option is A ${s p}^{2}$
In butenedioic acid, all carbon atoms undergo $s p^{2}$ hybridization. Because all carbon atoms are attached with at least one double bond.
Hence, option A is correct.

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s p, s p^{2} a n d s p^{3}

The state of hybridization of boron and oxygen atoms in boric acid $(H_{3} B O_{3})$ are respectively:

C H_{4}, C_{2} H_{6}, a n d C_{2} H_{4}

(N_{3}^{-}, N O C l, N_{2} O)

{s p}^{3}

{s p}^{2}

s p

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