The hybridization state of carbocation is :

s p^{3} d

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s p^{3}

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s p^{2}

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Solution

The correct option is C $s p^{2}$
A carbocation contains 3 bond pairs and 0 lone pairs. Hence, it is $s p^{2}$ hybridized.

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Question 03

The types of hybrid orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}$ respectively are expected to be

(a) $s p, s p^{3} a n d s p^{2}$

(b) $s p, s p^{2} a n d s p^{3}$

(d) $s p^{2}, s p^{3} a n d s p$

L i H + {B - -}_{2} H_{6} \to 2 L i B - - H_{4}

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B F_{3}

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