The hybridization state of carbon atoms in the product formed by the reaction of ethyl chloride with aqueous KOH is:
A
sp
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B
sp2
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C
sp3
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D
sp3d
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Solution
The correct option is Bsp3 Ethyl chloride( C2H5Cl) is a primary halogenoalkane which undergoes substitution reaction in the presence of aq.KOH. The equation can be written as: C2H5Cl+KOH→C2H5OH+KCl Therefore the carbon atoms in the alcohol formed are sp3 hybridised.