The hybridization state of Carbon in diamond is:

sp²

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sp³

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None of these

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Solution

The correct option is B
sp³

In diamond each carbon atom undergoes sp³ hybridisation and linked to four other carbon atoms by using hybridised orbitals in tetrahedral fashion.

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s p, s p^{2} a n d s p^{3}

s p, s p^{2}

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C H_{4}, C_{2} H_{6}, a n d C_{2} H_{4}

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