The hybridization states of central atoms of the ions $I_{3}^{-}, I C l_{4}^{-} a n d I C l_{2}^{-}$ are respectively :

s p^{2}, d s p^{2}, s p^{3}

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s p^{3} d, s p^{3} d^{2} a n d s p^{3} d

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s p^{3} d, s p^{3} d, d s p^{2}

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s p, s p, d s p^{2}

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Solution

The correct option is C $s p^{3} d, s p^{3} d^{2} a n d s p^{3} d$
$I_{3}^{-}$ is a $A B_{2} E_{3}$ type molecule where A is central atom, B is bond pair and E is electron pair. This type of molecule according to VSEPR theory shows
Electronic Structure: $A B_{2} E_{3}$
Electronic Geometry: trigonal bipyramidal
Hybridization at central atom: $s p^{3} d$
$I C l_{4}^{-}$ is $A B_{4} E_{2}$ molecule and it shows
Electronic Structure: $A B_{4} E_{2}$
Electronic Geometry: Octahedral
Hybridization at central atom: $s p^{3} d^{2}$
$I {C l}_{2}^{-}$ is $A B_{2} E_{3}$ and it shows
Electronic Structure: $A B_{2} E_{3}$
Electronic Geometry: Trigonal bipyramidal
Hybridization at central atom: $s p^{3} d$

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Similar questions

The correct order of hybridization of the central atom in the following species $N H_{3}, [P t C l_{4}]^{2 -}$ , $P C l_{5}$ and $B C l_{3}$ is

The correct order of hybridisation of the central atom in the following species $N H_{3}$ , ${[P t C l_{4}]}^{2 -}$ , $P C l_{5}$ and $B C l_{3}$

[N i C l_{4}]^{2 -}, [N i (C N)_{4}]^{2 -} & [N i (C O)_{4}]

[N i (C O)_{4}]

[N i (C N)_{4}]^{2 -}

The hybridisation present in $C_{2} H_{2}$ is

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Electronic Structure:	$A B_{2} E_{3}$
Electronic Geometry:	trigonal bipyramidal
Hybridization at central atom:	$s p^{3} d$

Electronic Structure:	$A B_{4} E_{2}$
Electronic Geometry:	Octahedral
Hybridization at central atom:	$s p^{3} d^{2}$